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    Calculates locally in your browser · ACI 318-19 Chapter 17
    Concrete / Anchors

    Concrete anchor design

    A cast-in anchor rarely fails in the steel — it pulls out a cone of concrete. This checks steel tension, concrete breakout, pullout, steel shear and pryout, and names which one governs, with every coefficient exposed.

    Embedment120 mmEdge distance180 mmConcreteC30
    Governing
    Concrete breakout, tension
    40% utilised
    Breakout capacity
    50.4 kN
    ANc 1.296e+5 mm²
    Steel capacity
    94.2 kN
    Ase 157 mm²
    Verdict
    Pass
    M16, hef 120 mm
    Chapter 17 checks
    Tension states against the tension demand, shear states against shear.
    Chapter 17 checks
    Limit stateNominal (kN)φDesign (kN)Utilisation
    Steel tension125.60.7594.221%
    Concrete breakout, tension ◂72.00.7050.440%
    Pullout96.00.7067.230%
    Steel shear75.40.6549.020%
    Pryout144.00.70100.810%

    Nb = 10·λa·√f'c·hef^1.5, ANc/ANco = 1.00, ψed = 1.00.

    Inspect the model
    Choose a quick result view, a scaled comparison, or the complete diagnostic set.
    Breakout capacity against embedment
    Capacity grows with hef^1.5 — depth is worth more than diameter.
    Breakout capacity against embedment0.00033.9667.92101.88135.83169.7960 mm60 mm80 mm80 mm100 mm100 mm120 mm120 mm150 mm150 mm200 mm200 mm250 mm250 mmφNcb (kN)
    Canonical equations
    The exact relationships implemented by this engine.

    φNsa = 0.75 · Ase · futa · The anchor itself.

    Ncb = (ANc/ANco)·ψed·Nb, Nb = 10·λa·√f'c·hef^1.5 · kc = 10 in SI for cast-in anchors.

    Np = 8 · Abrg · f'c · Headed anchor bearing on the concrete.

    engineering methodology

    A clear path from inputs to results.

    A cast-in anchor rarely fails in the steel. It pulls out a cone of concrete whose size scales with the embedment to the power of 1.5, which is why depth buys far more capacity than diameter. This checks the five limit states that decide it.

    Step-by-step methodWorked exampleAssumptions explained

    How to use

    1. Enter the anchor diameter, embedment and edge distance.
    2. Set the concrete strength and the anchor steel strength.
    3. Read the governing state — breakout usually wins at shallow embedment.

    The formula

    Ncb=ANcANcoψedNb,Nb=10λafc′ hef1.5N_{cb} = \frac{A_{Nc}}{A_{Nco}}\psi_{ed} N_b, \qquad N_b = 10\lambda_a\sqrt{f'_c}\,h_{ef}^{1.5}

    Reference: ACI 318-19 §17.6.2 (breakout), §17.6.3 (pullout), §17.7 (shear), φ = 0.70.

    Worked example

    M16 at 120 mm embedment in C30

    Inputs
    • Ase 157 mm², futa 800 MPa, edge distance 180 mm.
    Calculation path
    1. 1

      Steel φNsa = 0.75 × 157 × 800 = 94.2 kN. Nb = 10 × √30 × 120^1.5 = 72.0 kN; with the full cone ANc/ANco = 1 and ψed = 1, φNcb = 50.4 kN. Pullout φNp = 0.70 × 8 × 400 × 30 = 67.2 kN.

    Result

    Concrete breakout governs at 50.4 kN.

    Interpreting the result

    Breakout is a concrete failure, not a steel one: doubling the embedment multiplies the capacity by 2.8, while doubling the diameter only doubles the steel strength.

    Assumptions & limitations

    • Cast-in anchors with kc = 10 (SI).
    • Tension and shear checked separately; interaction is noted, not computed.
    • Shear breakout and side-face blowout are not included.
    • No supplementary reinforcement is counted.

    Frequently asked questions

    Why does embedment matter more than diameter?

    Breakout capacity scales with hef^1.5 because the cone surface area grows with the square of the depth.

    What is pryout?

    A shear load levering a shallow anchor out of the concrete; kcp doubles once hef reaches 65 mm.

    When does pullout govern?

    For a headed anchor with a small head bearing area relative to the embedment.

    Can I use this for post-installed anchors?

    Only with the manufacturer’s qualification data; the kc and pullout values differ for adhesive and mechanical anchors.

    Methodology last reviewed 2026-10-22. Results are informational and not financial or engineering advice — see our disclaimer.