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    Calculates locally in your browser · AWG geometry and voltage drop
    Wiring / conductor sizing

    Wire gauge and voltage drop

    Convert an AWG size into real conductor geometry, then check the load current against ampacity and compute the round-trip voltage drop over the run. Copper and aluminium are both supported.

    Load checkWithin limitCopper loss147.46 WResistivity1.724e−8
    Conductor area
    5.261 mm²
    2.588 mm diameter
    Voltage drop
    4.915 V
    2.14% of 230 V
    Loop resistance
    163.842 mΩ
    Over 25.0 m each way
    Ampacity
    30 A
    Load is within the limit
    AWG conductor table
    Diameter, cross-section and resistance for each common size, with the ampacity used here.
    Copper
    AWG conductor table
    AWGDiameterAreaΩ per kmAmpacity
    14 AWG1.628 mm2.081 mm²8.28515 A
    12 AWG2.053 mm3.309 mm²5.21020 A
    10 AWG2.588 mm5.261 mm²3.27730 A
    8 AWG3.264 mm8.366 mm²2.06140 A
    6 AWG4.115 mm13.302 mm²1.29655 A
    4 AWG5.189 mm21.151 mm²0.81570 A
    3 AWG5.827 mm26.670 mm²0.64685 A
    2 AWG6.544 mm33.631 mm²0.51395 A
    1 AWG7.348 mm42.408 mm²0.407110 A
    0 AWG8.251 mm53.475 mm²0.322125 A

    Ampacity figures are the 60 °C copper column, derated 22% for aluminium. Installation method and ambient temperature change the real limit.

    Inspect the model
    Choose a quick result view, a scaled comparison, or the complete diagnostic set.
    Voltage drop by run length
    Round-trip drop at the selected current and conductor size.
    Voltage drop by run length0.0009.2818.5627.8437.1246.400.9835 m5 m1.9710 m10 m4.9225 m25 m9.8350 m50 m19.66100 m100 m39.32200 m200 mDrop (V)
    Drop across the AWG range
    Each step of three AWG numbers roughly halves the cross-section and doubles the drop.
    Drop across the AWG range0.0002.785.578.3511.1313.9214141212101088664433221100Drop (V)
    Canonical equations
    The exact relationships implemented by this engine.

    d = 0.127·92^((36−n)/39) · n = AWG number

    A = πd²/4 · circular mils ÷ 1.273e6 gives mm² too

    r = ρ/A · r is resistance per metre; ρ is temperature dependent

    V_d = I·R_loop = 2·I·r·L · the factor 2 covers both conductors

    engineering methodology

    A clear path from inputs to results.

    Wire sizing is two separate checks that often disagree: will the conductor carry the current without overheating, and will the voltage still be usable at the far end? This engine computes the geometry from the AWG definition, then runs both checks on the same conductor.

    Step-by-step methodWorked exampleAssumptions explained

    How to use

    1. Select the AWG size. Lower numbers are thicker.
    2. Choose copper or aluminium.
    3. Enter the load current.
    4. Enter the one-way run length. The drop calculation doubles it for the return conductor.
    5. Enter the supply voltage to get the drop as a percentage.
    6. Check both badges: ampacity for safety, voltage drop for performance.

    The formula

    d=0.127⋅92(36−n)/39 mm,A=πd24,R=ρLA,Vd=2IRLd = 0.127 \cdot 92^{(36-n)/39}\ \text{mm}, \qquad A = \frac{\pi d^2}{4}, \qquad R = \frac{\rho L}{A}, \qquad V_d = 2IRL

    Reference: ASTM B258 (AWG diameters); NEC Article 310.16 (ampacity tables); IEC 60228 for metric equivalents.

    Worked example

    10 AWG copper, 30 A, 25 m run at 230 V (default inputs)

    Inputs
    • 10 AWG copper.
    • Load 30 A.
    • Run length 25 m each way.
    • Supply 230 V.
    Calculation path
    1. 1

      Diameter: 0.127 × 92^(26/39) = 2.588 mm; area = 5.261 mm².

    2. 2

      Resistance: 1.724×10⁻⁸ / 5.261×10⁻⁶ = 3.277 Ω per km.

    3. 3

      Loop resistance over 25 m each way: 0.0819 Ω.

    4. 4

      Voltage drop: 2 × 30 × 0.0819 = 4.915 V, or 2.14% of 230 V.

    5. 5

      Ampacity at 60 °C is 30 A, so the load is exactly at the limit.

    Result

    5.26 mm² · 3.28 Ω/km · 4.92 V drop (2.14%) · 30 A ampacity — within the limit but with no margin.

    Interpreting the result

    Both checks pass here, but only just. The 2.14% drop is inside the 3% branch-circuit guideline, and the current exactly equals the ampacity column. Real installations need margin: derating for ambient temperature, conduit fill and bundling can cut ampacity by 20% or more, which would make 10 AWG inadequate at 30 A.

    Assumptions & limitations

    • Resistivity is at 20 °C. Copper rises about 0.4% per kelvin, so a conductor at 70 °C has roughly 20% more resistance and more drop.
    • Ampacity uses the 60 °C copper column, derated 22% for aluminium. Insulation rating and installation method change this materially.
    • The load is resistive with unity power factor. Reactive loads need the impedance rather than the resistance.
    • The run is a simple two-wire circuit. Three-phase runs drop the factor of 2 and use √3 instead.
    • No derating for ambient temperature, conduit fill, or adjacent conductors is applied.

    Frequently asked questions

    What does AWG actually measure?

    Cross-sectional area, encoded logarithmically: each three-gauge step halves the area, and each six-gauge step halves the diameter. The formula reproduces the historical wire-drawing process.

    Which limit governs, ampacity or voltage drop?

    Ampacity is a safety limit and must never be exceeded. Voltage drop is a performance limit. On short runs ampacity governs; on long runs voltage drop usually does.

    Does this handle three-phase?

    No — it models a single-phase two-wire circuit. For three-phase, the drop is √3 × I × R × L and the current per conductor is lower for the same power.

    Why is aluminium derated?

    It has about 61% of copper’s conductivity, so the same cross-section carries less current for the same temperature rise. Aluminium also creeps under terminal pressure, which is why it needs different connectors.

    How much voltage drop is acceptable?

    Common guidance is 3% for a branch circuit and 5% total from the service entrance. Equipment tolerances and motor starting currents can demand tighter limits.

    Why does my calculated drop differ from a cable manufacturer’s table?

    Manufacturers quote impedance at operating temperature and include reactance, which matters for large conductors and high currents. This engine uses DC resistance at 20 °C, so it understates drop on big cables.

    Methodology last reviewed 2026-10-18. Results are informational and not financial or engineering advice — see our disclaimer.