Wire gauge and voltage drop
Convert an AWG size into real conductor geometry, then check the load current against ampacity and compute the round-trip voltage drop over the run. Copper and aluminium are both supported.
| AWG | Diameter | Area | Ω per km | Ampacity |
|---|---|---|---|---|
| 14 AWG | 1.628 mm | 2.081 mm² | 8.285 | 15 A |
| 12 AWG | 2.053 mm | 3.309 mm² | 5.210 | 20 A |
| 10 AWG | 2.588 mm | 5.261 mm² | 3.277 | 30 A |
| 8 AWG | 3.264 mm | 8.366 mm² | 2.061 | 40 A |
| 6 AWG | 4.115 mm | 13.302 mm² | 1.296 | 55 A |
| 4 AWG | 5.189 mm | 21.151 mm² | 0.815 | 70 A |
| 3 AWG | 5.827 mm | 26.670 mm² | 0.646 | 85 A |
| 2 AWG | 6.544 mm | 33.631 mm² | 0.513 | 95 A |
| 1 AWG | 7.348 mm | 42.408 mm² | 0.407 | 110 A |
| 0 AWG | 8.251 mm | 53.475 mm² | 0.322 | 125 A |
Ampacity figures are the 60 °C copper column, derated 22% for aluminium. Installation method and ambient temperature change the real limit.
d = 0.127·92^((36−n)/39) · n = AWG number
A = πd²/4 · circular mils ÷ 1.273e6 gives mm² too
r = ρ/A · r is resistance per metre; ρ is temperature dependent
V_d = I·R_loop = 2·I·r·L · the factor 2 covers both conductors
A clear path from inputs to results.
Wire sizing is two separate checks that often disagree: will the conductor carry the current without overheating, and will the voltage still be usable at the far end? This engine computes the geometry from the AWG definition, then runs both checks on the same conductor.
How to use
- Select the AWG size. Lower numbers are thicker.
- Choose copper or aluminium.
- Enter the load current.
- Enter the one-way run length. The drop calculation doubles it for the return conductor.
- Enter the supply voltage to get the drop as a percentage.
- Check both badges: ampacity for safety, voltage drop for performance.
The formula
Reference: ASTM B258 (AWG diameters); NEC Article 310.16 (ampacity tables); IEC 60228 for metric equivalents.
Worked example
10 AWG copper, 30 A, 25 m run at 230 V (default inputs)
- 10 AWG copper.
- Load 30 A.
- Run length 25 m each way.
- Supply 230 V.
- 1
Diameter: 0.127 × 92^(26/39) = 2.588 mm; area = 5.261 mm².
- 2
Resistance: 1.724×10⁻⁸ / 5.261×10⁻⁶ = 3.277 Ω per km.
- 3
Loop resistance over 25 m each way: 0.0819 Ω.
- 4
Voltage drop: 2 × 30 × 0.0819 = 4.915 V, or 2.14% of 230 V.
- 5
Ampacity at 60 °C is 30 A, so the load is exactly at the limit.
5.26 mm² · 3.28 Ω/km · 4.92 V drop (2.14%) · 30 A ampacity — within the limit but with no margin.
Interpreting the result
Both checks pass here, but only just. The 2.14% drop is inside the 3% branch-circuit guideline, and the current exactly equals the ampacity column. Real installations need margin: derating for ambient temperature, conduit fill and bundling can cut ampacity by 20% or more, which would make 10 AWG inadequate at 30 A.
Assumptions & limitations
- Resistivity is at 20 °C. Copper rises about 0.4% per kelvin, so a conductor at 70 °C has roughly 20% more resistance and more drop.
- Ampacity uses the 60 °C copper column, derated 22% for aluminium. Insulation rating and installation method change this materially.
- The load is resistive with unity power factor. Reactive loads need the impedance rather than the resistance.
- The run is a simple two-wire circuit. Three-phase runs drop the factor of 2 and use √3 instead.
- No derating for ambient temperature, conduit fill, or adjacent conductors is applied.
Frequently asked questions
What does AWG actually measure?
Cross-sectional area, encoded logarithmically: each three-gauge step halves the area, and each six-gauge step halves the diameter. The formula reproduces the historical wire-drawing process.
Which limit governs, ampacity or voltage drop?
Ampacity is a safety limit and must never be exceeded. Voltage drop is a performance limit. On short runs ampacity governs; on long runs voltage drop usually does.
Does this handle three-phase?
No — it models a single-phase two-wire circuit. For three-phase, the drop is √3 × I × R × L and the current per conductor is lower for the same power.
Why is aluminium derated?
It has about 61% of copper’s conductivity, so the same cross-section carries less current for the same temperature rise. Aluminium also creeps under terminal pressure, which is why it needs different connectors.
How much voltage drop is acceptable?
Common guidance is 3% for a branch circuit and 5% total from the service entrance. Equipment tolerances and motor starting currents can demand tighter limits.
Why does my calculated drop differ from a cable manufacturer’s table?
Manufacturers quote impedance at operating temperature and include reactance, which matters for large conductors and high currents. This engine uses DC resistance at 20 °C, so it understates drop on big cables.
Methodology last reviewed 2026-10-18. Results are informational and not financial or engineering advice — see our disclaimer.