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    Calculates locally in your browser · conductor ampacity and derating
    Electrical / conductors

    Cable ampacity and derating

    The ampacity table assumes 30 °C ambient and three current-carrying conductors. The calculator applies temperature and conductor-count corrections, the terminal temperature cap, continuous-load sizing, a selected breaker/fuse check including supported NEC 240.4(D) limits, and voltage drop.

    Ampacity100%Ambient30 °CDropWithin 3%
    Derated ampacity
    30.0 A
    after correction and adjustment; capped at 30 A by the terminal limit
    Design load
    30.0 A
    125% of a continuous load
    Voltage drop
    2.48%
    6.0 V over 100 ft
    Overcurrent device
    30 A
    allowable up to 30.0 A
    Verdict
    Passes
    selected size passes ampacity, protection and drop checks
    Ampacity build-up
    The table value, Article 310 corrections and adjustment, then the termination-temperature limit.
    30 A
    Ampacity build-up
    StepValueNote
    Conductor10 AWG/kcmil copper75 °C insulation
    Table 310.16 ampacity35 A30 °C ambient, three conductors
    Ambient correction1.000Table 310.15(B)(1) at 30 °C
    Conductor adjustment1.000Table 310.15(C)(1), 3 current-carrying
    Corrected ampacity35.0 Aafter ambient correction and conductor adjustment
    Termination limit30 A60 °C table ampacity per §110.14(C)
    Permitted ampacity30.0 Alower of corrected ampacity and termination limit
    Load current24.0 Acontinuous
    Design load30.0 A125% per §210.19
    Ampacity checkPass100% utilised
    Overcurrent device30 Aselected circuit-breaker/fuse rating
    Maximum device rating30.0 Aincludes §240.4(D) 30 A ceiling
    Protection checkPassdevice must cover design load and protect conductor
    DC resistance1.2400 Ω/kFTChapter 9, Table 8 at 75 °C
    Voltage drop5.95 V2.48% of 240 V
    Drop limit3%branch circuit, §210.19 informational note
    Recommended size10selected size passes ampacity, protection and drop checks

    The 125% rule applies to the load, not the conductor: a continuous load is taken at 125% and then compared with the derated ampacity. Applying it twice is the most common error in a panel schedule.

    Inspect the model
    Choose a quick result view, a scaled comparison, or the complete diagnostic set.
    Derated ampacity against ambient
    Every five degrees above 30 °C costs 4–6% of the conductor’s capacity.
    Derated ampacity against ambient0.0006.7213.4420.1626.8833.6020°C20°C25°C25°C30°C30°C35°C35°C40°C40°C45°C45°C50°C50°C55°C55°C60°C60°CAmps
    Voltage drop against length
    Linear in length and in current; the 3% line is where the next size up becomes cheaper than the losses.
    Voltage drop against length0.0002.344.687.029.3611.711.2450502.481001003.721501504.962002007.443003009.92400400Percent
    Canonical equations
    The exact relationships implemented by this engine.

    I′ = I_table × f_temp × f_bundle · Both factors from Article 310.

    I_allow = min(I′, I_terminal) · The terminal temperature column caps the corrected value under §110.14(C).

    I_design = 1.25 × I_load · §210.19(A)(1) for branch circuits.

    VD = 2·L·I·R/1000 · Single phase; √3 replaces 2 for three phase.

    I_design ≤ I_OCPD ≤ min(I_allow, I_240.4(D)) · Small-conductor ceiling applies where relevant; exceptions are not evaluated.

    I_allow ≥ I_design; I_OCPD passes; VD ≤ 3% · All selected checks must hold.

    engineering methodology

    A clear path from inputs to results.

    The ampacity table assumes 30 °C ambient and three current-carrying conductors. The calculator corrects for temperature and conductor count, caps ampacity at the selected terminal rating, checks the selected fuse or breaker against the conductor and NEC 240.4(D) where applicable, and checks voltage drop.

    Step-by-step methodWorked exampleAssumptions explained

    How to use

    1. Pick the conductor size, material and insulation rating.
    2. Set the terminal temperature, ambient temperature and number of current-carrying conductors.
    3. Enter the load current and say whether it is continuous.
    4. Select the installed overcurrent-device rating, then read ampacity, protection, voltage drop and recommended size checks.

    The formula

    Iallow=min⁡(Itableftempfconductors,Iterminal);Idesign=1.25Icontinuous;Idesign≤IOCPD≤min⁡(Iallow,I240.4(D))I_{allow}=\min(I_{table}f_{temp}f_{conductors},I_{terminal});\quad I_{design}=1.25I_{continuous};\quad I_{design}\le I_{OCPD}\le\min(I_{allow},I_{240.4(D)})

    Reference: NFPA 70 (NEC) Tables 310.16, 310.15(B)(1), 310.15(C)(1), §§110.14(C), 210.19(A)(1), 240.4(D); resistance from Chapter 9, Table 8.

    Worked example

    10 AWG copper at 24 A, 100 ft, 240 V

    Inputs
    • 10 AWG copper, 75 °C insulation.
    • 60 °C terminations and a selected 30 A circuit breaker.
    • 30 °C ambient, three current-carrying conductors.
    • 24 A continuous load, 100 ft one-way, 240 V single phase.
    Calculation path
    1. 1

      Table 310.16 gives 35 A for 10 AWG copper at 75 °C.

    2. 2

      At 30 °C the ambient factor is 1.00 and three conductors need no adjustment, so corrected ampacity is 35 A before the terminal cap.

    3. 3

      The 60 °C terminal column limits this conductor to 30 A. A continuous load is taken at 125%, so the design load is 24 × 1.25 = 30 A.

    4. 4

      NEC 240.4(D) limits 10 AWG copper protection to 30 A; the selected 30 A breaker meets the calculator's protection check.

    5. 5

      The conductor resistance is 1.24 Ω per 1000 ft, so the drop is 2 × 100 × 24 × 1.24 / 1000 = 5.95 V.

    6. 6

      That is 2.48% of 240 V, inside the 3% branch-circuit limit.

    7. 7

      The selected 30 A device covers the 30 A design load and meets the small-conductor limit; ampacity is fully used and voltage drop passes.

    Result

    30 A permitted · 30 A design · 30 A OCPD · 2.48% drop · passes.

    Interpreting the result

    Ampacity, overcurrent protection and voltage drop are separate checks. Upsizing the conductor can address ampacity, a too-large breaker or fuse, or voltage drop; an overcurrent device below the design load needs a different device selection, not wire upsizing alone.

    Assumptions & limitations

    • Ampacities are the NEC Table 310.16 values for not more than three current-carrying conductors in a raceway or cable at 30 °C.
    • Ambient correction and conductor adjustment multiply, and both are applied to the table value.
    • Resistance is the DC value at 75 °C from Chapter 9, Table 8; reactance is neglected.
    • Voltage drop uses 2LI R for single phase and √3LI R for three phase.
    • The selected terminal temperature caps ampacity; follow equipment markings/listing instructions. The selected overcurrent device is checked against corrected ampacity and the §240.4(D) ceilings supported by this calculator (14/12/10 AWG).
    • §240.4(B), (E) and (G) exceptions, motor circuits and other special overcurrent rules are not evaluated; the protection check is conservative and may reject a permitted exception.

    Frequently asked questions

    Why can't I use the 90 °C column?

    Use the insulation column for ambient/conductor-count corrections, then cap the result at the terminal temperature shown on listed equipment. A 90 °C conductor with 75 °C terminations is therefore limited to the lower 75 °C ampacity; the selected rating must match equipment markings and applicable code rules.

    Why 125% for a continuous load?

    Because a load that runs for three hours or more heats the conductor to its steady-state temperature, and the code wants margin against that. The 125% applies to the load, not to the conductor, and applying it twice is a common error.

    Does conduit fill affect ampacity?

    Not directly — ampacity depends on the number of current-carrying conductors, not on how full the conduit is. Fill is a separate requirement in Chapter 9, and both have to be satisfied.

    What counts as a current-carrying conductor?

    The ungrounded conductors and, in some cases, the neutral. A neutral that carries only the unbalanced current of a three-wire circuit does not count; one that carries the full load current, as on a 120 V circuit, does.

    What is the voltage-drop limit?

    3% for a branch circuit and 5% overall including the feeder, from the informational notes to §210.19 and §215.2. It is advisory rather than mandatory in the code itself, but equipment manufacturers specify it and inspectors enforce it.

    Methodology last reviewed 2026-10-21. Results are informational and not financial or engineering advice — see our disclaimer.