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    Mechanical / Shafts

    Torsional Vibration

    The fundamental torsional natural frequency of a shaft. A drive train that sits on a torsional resonance will fatigue a coupling or a gearbox long before it fails in steady torque.

    Fundamental frequency1321.8 HzWave speed3172 m/sPolar moment127.23 ×10⁻⁸ m⁴
    Fundamental frequency
    1321.8 Hz
    Free–free shaft
    Wave speed
    3172 m/s
    √(G/ρ)
    Polar moment
    127.23 ×10⁻⁸ m⁴
    J for a solid shaft
    Critical speed
    7.931e+4 rpm
    First torsional node
    Frequency against length
    Free–free shaft: f = (1/2L)·√(G/ρ).
    Frequency against length
    Length (m)Frequency (Hz)
    0.53172.3
    11586.2
    1.51057.4
    2793.1
    3528.7
    Inspect the model
    Choose a quick result view, a scaled comparison, or the complete diagnostic set.
    Frequency against shaft length
    Inverse in length: doubling the shaft halves the frequency.
    Frequency against shaft length0.000710.601421.202131.812842.413553.010.5 m0.5 m1 m1 m1.5 m1.5 m2 m2 m3 m3 mTorsional Vibration
    Canonical equations
    The exact relationships implemented by this engine.

    f = (1/2L)·√(G/ρ) · Free–free torsional mode.

    c = √(G/ρ) · About 3,170 m/s for steel.

    engineering methodology

    A clear path from inputs to results.

    The fundamental torsional natural frequency of a shaft. A drive train that sits on a torsional resonance will fatigue a coupling or a gearbox long before it fails in steady torque.

    Step-by-step methodWorked exampleAssumptions explained

    How to use

    1. Set shaft length (m).
    2. Set diameter (mm).
    3. Set shear modulus (gpa).
    4. Set density (kg/m³).
    5. Read the headline metrics, then check the table for the detail.

    The formula

    f=(1/2L)⋅√(G/ρ)f = (1/2L)·√(G/ρ)

    Reference: Free–free torsional mode of a uniform shaft.

    Worked example

    At the default inputs

    Inputs
    • Shaft length (m): 1.2; Diameter (mm): 60; Shear modulus (GPa): 79; Density (kg/m³): 7850
    Calculation path
    1. 1

      Fundamental frequency: 1321.8 Hz · Wave speed: 3172 m/s · Polar moment: 127.23 ×10⁻⁸ m⁴ · Critical speed: 7.931e+4 rpm

    Result

    Fundamental frequency: 1321.8 Hz · Wave speed: 3172 m/s · Polar moment: 127.23 ×10⁻⁸ m⁴

    Interpreting the result

    A 1.2 m shaft rings at 1322 Hz, or 7.931e+4 rpm.

    Assumptions & limitations

    • Uniform shaft, free ends.
    • No attached inertia such as a flywheel.

    Frequently asked questions

    What changes with a flywheel?

    A large inertia at one end lowers the frequency and adds modes.

    How do I avoid resonance?

    Keep the operating speed well away from the critical, or add a damper.

    Methodology last reviewed 2026-10-22. Results are informational and not financial or engineering advice — see our disclaimer.