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    Structural / Fire

    Steel Fire Resistance Check

    Unprotected steel heats quickly because it has little mass for its surface. EN 1993-1-2 gives the critical temperature from the utilisation and the heating rate from the section factor; the intersection is the time to failure in a standard fire.

    StandardEN 1993-1-2Section180 m⁻¹ResultPass
    Critical temperature
    585 °C
    At μ₀ 0.50
    Time to critical
    > duration
    Meets the requirement
    Steel at duration
    190 °C
    60 min standard fire
    Utilisation
    50%
    At the fire limit state
    Steel temperature in the standard fire
    Unprotected member, ISO 834 fire curve.
    Steel temperature in the standard fire
    MinutesSteel (°C)State
    1542Below
    3083Below
    45133Below
    60190Below
    90—Below
    120—Below

    A coated member needs the insulation thickness, not this curve.

    Inspect the model
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    Steel temperature against time
    Critical temperature 585 °C.
    Steel temperature against time0.00039.8779.74119.62159.49199.3611881515222229293636434350505757°C
    Canonical equations
    The exact relationships implemented by this engine.

    θcr = 39.19·ln(1/(0.9674·μ₀^3.833) − 1) + 482 · EN 1993-1-2 §4.2.4.

    Δθ = (Am/V)/(ca·ρa)·h·Δt · Unprotected steel, §4.2.5.2.

    θg = 20 + 345·log₁₀(8t + 1) · ISO 834 standard fire, t in minutes.

    engineering methodology

    A clear path from inputs to results.

    Unprotected steel heats quickly because it has little mass for its surface. EN 1993-1-2 gives the critical temperature from the utilisation and the heating rate from the section factor; the intersection is the time to failure in a standard fire.

    Step-by-step methodWorked exampleAssumptions explained

    How to use

    1. Set section factor am/v (m⁻¹).
    2. Set utilisation μ₀ at fire limit state.
    3. Set required fire resistance (min).
    4. Set resultant emissivity ε.
    5. Read the headline metrics, then check the table for the detail.

    The formula

    θcr=39.19ln⁡ ⁣(10.9674 μ03.833−1)+482\theta_{cr} = 39.19\ln\!\left(\frac{1}{0.9674\,\mu_0^{3.833}} - 1\right) + 482

    Reference: EN 1993-1-2 §4.2.4 (critical temperature) and §4.2.5.2 (unprotected heating).

    Worked example

    At the default inputs

    Inputs
    • Section factor Am/V (m⁻¹): 180; Utilisation μ₀ at fire limit state: 0.5; Required fire resistance (min): 60; Resultant emissivity ε: 0.7
    Calculation path
    1. 1

      Critical temperature → 585 °C Heat the section → — min

    Result

    Critical temperature: 585 °C · Time to critical: > duration · Steel at duration: 190 °C

    Interpreting the result

    At 50% utilisation the critical temperature is 585 °C; an unprotected 180 m⁻¹ section reaches it in more than the fire duration, so the 60-minute requirement is met.

    Assumptions & limitations

    • Unprotected steel; no intumescent coating or boarding.
    • ISO 834 standard fire.
    • Uniform temperature through the section.

    Frequently asked questions

    Why does a higher Am/V fail sooner?

    More surface per unit mass means faster heating.

    Does coating change the answer?

    Yes; the insulation thickness is a separate calculation.

    Methodology last reviewed 2026-10-23. Results are informational and not financial or engineering advice — see our disclaimer.